120*2=3(3^n-1)

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Solution for 120*2=3(3^n-1) equation: 



120*2=3(3^n-1)

We move all terms to the left:

120*2-(3(3^n-1))=0

We add all the numbers together, and all the variables

-(3(3^n-1))+240=0



We calculate terms in parentheses: -(3(3^n-1)), so:

3(3^n-1)

We multiply parentheses

9n-3

Back to the equation:

-(9n-3)



We get rid of parentheses

-9n+3+240=0

We add all the numbers together, and all the variables

-9n+243=0

We move all terms containing n to the left, all other terms to the right

-9n=-243

n=-243/-9

n=+27

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